F(2)=(2)^2-4x+5

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Solution for F(2)=(2)^2-4x+5 equation: 



(2)=(2)^2-4F+5

We move all terms to the left:

(2)-((2)^2-4F+5)=0

We get rid of parentheses

4F-5+2-2^2=0

We add all the numbers together, and all the variables

4F-7=0

We move all terms containing F to the left, all other terms to the right

4F=7

F=7/4

F=1+3/4

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